Battery shown in figure, has emf E and internal resistance r. Current in the circuit can be varied by sliding the contact J.

If at an instant current flowing through the circuit is i, potential difference between terminals of the cell is V, thermal power generated in external circuit is P and thermal power generated in the cell is equal to η fraction of total electrical power generated in it, then which of the following graphs are correct?
Text Solution
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(a, b, d)
Potential difference across the terminals of a cell is given by: V = E – ir. Hence, the graph between V and I will be a straight line having negative slope and a positive intercept on V-axis. Hence, the option is correct.
Total electric power generated in the cell is equal to Ei and thermal power generated in the cell is equal to i 2 r. Hence, the thermal power generated in the external circuit is P = Ei – i 2 r. Hence, the graph between P and I will be a parabola passing through origin, the slope of the parabola will be equal to
= E – 2ir.
Hence, the slope of the curve will be maximum at r = 0 and then it decreases gradually but remains positive. Hence, the option is also correct. When terminal potential difference across the cell is V, current flowing through the circuit will be i = (E – V)/r and thermal power generated in the external circuit will be equal to
P = Vi = V(E – V)/r
Hence, the graph between P and V will be a parabola passing through origin and having maximum value of P at V = E/2. Hence, the option is also correct.

At an instant, thermal power generated in the cell is equal to i 2 r and total electrical power generated in the cell is equal to Ei. Hence, the fraction η =
or, η =
i or, η ∝ i.
Hence, the graph between η and i will be a straight line passing through origin and having a positive slope as shown in figure. Hence, the option is wrong.
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